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3x^2+18=x^2
We move all terms to the left:
3x^2+18-(x^2)=0
We add all the numbers together, and all the variables
2x^2+18=0
a = 2; b = 0; c = +18;
Δ = b2-4ac
Δ = 02-4·2·18
Δ = -144
Delta is less than zero, so there is no solution for the equation
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